#define N 10000

int mpNum2Long(unsigned long *ul, int *num)
{
    unsigned long maxUL, maxULdivN;
    unsigned long x;
    int      *nn;

    maxUL = ~0;
    maxULdivN = maxUL / N;

    x = 0;
    for (nn = num + *num; nn != num; ) {
        if (x > maxULdivN) return -1;
        x *= N;
        if (*nn > maxUL - x) return -1;
        x += *nn--;
    }
    *ul = x;

    return 0;
}